A list of possibilities:
A=(1,9),(2,8),(3,7),(4,6)
B=(1,2),(2,3),(3,4),(4,5),(5,6),(6,7),(7,8),(8,9)
C=(3,8),(4,6)
D=(1,3),(2,6),(3,9)
5 can only be held by B and 7 can only be held by A or B.
Case 1
if B=(4,5) or (5,6) then
C=(3,8) then
D=(2,6) then
B=(4,5) (B=(5,6) will lead to contradiction becase 6 is replicated)
then
A=(1,9)
the remaining card is 7
Case 2
if B=(6,7) then
C=(3,8) then
D=(2,6) which lead to contradiction because 6 is replicated.
Case 3
if B=(7,8) then
C=(4,6) then
A=(1,9) then
D has no answer
Case 4
if A=(3,7) then
C=(4,6) then
D has no answer
Answer:
A=(1,9)
B=(4,5)
C=(3,8)
D=(2,6)
Remaining card=7
[ 本帖最後由 sheungwan 於 2007-5-29 14:09 編輯 ]